A potentiometer wire of length 200 cm has a resistance of 
. It is connected in series with a resistance of 10 
and an accumulator of emf 6 V having negligible internal resistance. A source of 2.4 V is balanced against a length L of the potentiometer wire. The value of L is
Text Solution
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The current in the potentiometer wire AB is
The potential difference across the potentiometer wire is
V = current ×resistance 
The length of the wire is 
So, the potential gradient along the wire is
The emf 
is balanced against a length L of the potentiometer wire.
i.e., 
or 
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